The modeled circuit is as follow:
to use the node voltage analysis we put the ground on the bottom and labeled the top two corners and the two junctions.
since we have 4 unknowns we have to write 4 equations.
Given
RC1=100Ω, RC2=RC1=220Ω, RL1=RL2=1KΩ
Vbat1=12V, Vbat2=9V
and the equations we should be able to solve the problem for V1, V2,V3, V4.
In this case V1 and V4 are easy to find since they are just equal to the battery voltages.
V1 = 12V and V4 = 9V.
Solving the equations gives, V2 = 10.2554V and V3 = 8.6736V.
Next to be able to construct the circuit we have to know the exact values of all the elements.
Vbat2 = V3 + ( Ibat2×RC3) = 8.75 + 0.0015×220 =9.08 ± 0.5 V
Pbat1 = 209.5 ± 2 mW
Pbat2 = 13.62 ± 2 mW
Now if we want V2 = V2 = 9V then by carrying the equation wrote earlier we obtain these values:
In order to get the precise values of the battery voltages we used the variable voltage sources.
The small amount of error in the results comes from the fact as always to make calculations easier we ignored the effects of wiring, which is minimal but still big enough to interfere.







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