the schematic for the circuit is as follow:
Without even graphing the linear relationship between the currents presents itself. As values of base currents increase the values for the emitter current change with almost the same amount.
Since IE=(1+β)IB then the equation for emitter current as a function of times becomes:
IE=IB+βIB , when compared to y=mx+b we can deduce that the β is the slope of the graph and the IB is the initial value. As a result β=0.968 and IB = 3.73. this value of base emitter is where the linear portion of their relationship starts. Also if we use resistor values below 1.9K or above 10K ohm we will be out of the linear portion of the currents relationships.



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